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🌟 Advent of Code (AoC) 2022 🌟

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Dag: 1
SprÄk: C#
Lösning: Github (Riktig ful lösning)

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Dag 1, Kotlin

fun dag1(x: Int) = input.split("\n\n").map { elf -> elf.lines().sumOf { snack -> snack.toInt() } }.sortedDescending().subList(0, x).sum()
println("Del 1: ${dag1(1)} och del 2: ${dag1(3)}")
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Dag: 1
SprÄk: Haskell

Kul att det Àr igÄng igen. Förra Äret kom jag till dag 9 tror jag. I Är ska jag försöka komma lÀngre och dessutom anstrÀnga mig att hÄlla lösningarna korta och lÀttlÀsta!

-- The program expects the input on stdin, ie
-- $ ./solve < input
import Data.List

main = interact solve

solve :: String -> String
solve input = "Problem 1: " ++ show (maximum list) ++ "\n"
           ++ "Problem 2: " ++ show (sum $ take 3 (reverse $ sort list)) ++ "\n"
    where list = makeList (lines input)

makeList :: [String] -> [Int]
makeList [] = []
makeList elves = sum (map read firstElf):makeList restOfTheElves
    where firstElf = takeWhile (/="") elves
          restOfTheElves = dropWhile (=="") (dropWhile(/="") elves)

(AnvÀnder "highlight" som finns i apt för syntaxfÀrgning.)

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Dag 1: Jag har tÀnkt rÀtt lÀnge att man borde ta och lÀra sig skriva rust nÄn gÄng so AoC Àr vÀl ett ypperligt tillfÀlle Jag har alltid varit lite rÀdd för att rust inte skulle lÄta en ignorera felkollar man inte ville hantera men det gick ju. HÀr Àr min första rustkod iaf:

use std::io::prelude::*;
use itertools::Itertools;

fn main() {
    let stdin = std::io::stdin();
    let lines: Vec<String> = stdin.lock().lines().flatten().collect();
    let res: Vec<i64> = lines.into_iter()
	// Group by empty lines
	.group_by(|elt| (*elt).is_empty()).into_iter()
	// parse and sum each group
	.map(|(_, group)| group.map(|elt| elt.parse::<i64>()).flatten().sum())
	// sort results (largest first)
	.sorted().rev().collect();

    let top3: i64 = res[..3].iter().sum();
    println!("{} {}", res[0], top3);
}
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Skrivet av kungowe:

Tjenare!
Tycker din lösning var elegant Men jag undrar hur din variabel input ser ut hÀr, vad har du gjort med din innan den skickas till funktionerna?

GÄ till inlÀgget

Tack

Jag har "bara" delat upp input pÄ \n\n, sÄ jag fÄr en lista med varje nisses rader för sig. Kika pÄ lÀnken i inlÀgget sÄ kan du se allting. Titta sÀrskilt pÄ utils.parse dÀr jag har en drös med parse-funktioner.

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Dag: 1
SprÄk: VB.Net

Imports System.IO

Module Program
    Sub Main(args As String())

        Dim elfs As New List(Of Integer)
        Dim currentElf As Integer = 0
        Using reader As New StreamReader("input.txt")
            While Not reader.EndOfStream
                Dim currentLine As String = reader.ReadLine()
                If Not String.IsNullOrWhiteSpace(currentLine) Then
                    currentElf += Integer.Parse(currentLine)
                Else
                    elfs.Add(currentElf)
                    currentElf = 0
                End If
            End While
        End Using

        elfs.Sort()
        elfs.Reverse()
        Console.WriteLine("Part 1: Most calories: " & elfs(0))
        Console.WriteLine("Part 2: Top 3: " & elfs(0) + elfs(1) + elfs(2))
    End Sub
End Module
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Dag: 1
SprÄk: Elixir
Lösning: Github

Mycket tid har gÄtt Ät till att tvinga hjÀrnan att sluta tÀnka imperativt.

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Dag: 1
SprÄk: C#
Lösning:

static void Main(string[] args)
{
    var splitArray = Input.TextInput.Split(Environment.NewLine + Environment.NewLine);
    var sumList = new List<int>();

    for (var i = 0; i < splitArray.Length; i++)
    {
        var individualIntArray = Array.ConvertAll(splitArray[i].Split(Environment.NewLine), x => int.Parse(x));

        sumList.Add(individualIntArray.Sum());
    }

    sumList = sumList.OrderByDescending(x => x).ToList();

    Console.WriteLine($"Answer 1: {sumList.First()}");
    Console.WriteLine($"Answer 2: {sumList.Take(3).Sum()}");
}
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Dag: 1
SprÄk: C++
Lösning:

#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
#include <vector>
#include <algorithm>
#include <numeric>

using namespace std;

//part 1

int main()
{

    string filename{"input.txt"};

    ifstream ifs{filename};

    vector<int> elves{};

    string line{};
    int temp{};
    getline(ifs, line);
    do
    {
        if (line == "")
        {
            elves.push_back(temp);
            temp = 0;
             getline(ifs, line);
        }

        temp += stoi(line);       
    }
    while (getline(ifs,line));

    cout << *max_element(elves.begin(), elves.end()) << endl;

    //part 2

    sort(elves.begin(), elves.end(), greater<int>());

    cout << accumulate(elves.begin(), elves.begin()+3, 0) << '\n';
}
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Jag Äterupptar fjolÄrets misslyckade försök att tentaplugga genom AOC. Pga alldeles för lite tid har bÄde C++ och den missade kursen hittills fÄtt alldeles för lite kÀrlek och det mÀrks nÀr jag mÄste lÀgga en timme pÄ att fÄ inlÀsningen rÀtt Förhoppningsvis slÀpper den vÀrsta ringrosten om nÄgra dagar

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Dag: 2
SprÄk: C#
Kvalité: Kompilerar och ger rÀtt svar! 

Console.WriteLine("Mickur's Advent of Code 2022 - Day 2!");

// Setup
var points = 0;

const int rockValue = 1;
const int paperValue = 2;
const int scissorValue = 3;

const int lossValue = 0;
const int drawValue = 3;
const int winValue = 6;

// Part One: Second column is what you're going to play
foreach (var line in File.ReadLines("input.txt"))
    switch (line[0])
    {
        // Enemy plays rock
        case 'A':
            switch (line[2])
            {
                // You play rock
                case 'X':
                    points += rockValue + drawValue;
                    break;

                // You play paper
                case 'Y':
                    points += paperValue + winValue;
                    break;

                // You play scissor
                case 'Z':
                    points += scissorValue + lossValue;
                    break;
            }

            break;

        // Enemy plays paper
        case 'B':
            switch (line[2])
            {
                // You play rock
                case 'X':
                    points += rockValue + lossValue;
                    break;

                // You play paper
                case 'Y':
                    points += paperValue + drawValue;
                    break;

                // You play scissor
                case 'Z':
                    points += scissorValue + winValue;
                    break;
            }

            break;

        // Enemy plays scissor
        case 'C':
            switch (line[2])
            {
                // You play rock
                case 'X':
                    points += rockValue + winValue;
                    break;

                // You play paper
                case 'Y':
                    points += paperValue + lossValue;
                    break;

                // You play scissor
                case 'Z':
                    points += scissorValue + drawValue;
                    break;
            }

            break;
    }

Console.WriteLine(points);

// Part Two: Seconds column is the result of the game
points = 0;

foreach (var line in File.ReadLines("input.txt"))
    switch (line[0])
    {
        // Enemy plays rock
        case 'A':
            switch (line[2])
            {
                // You should lose
                case 'X':
                    points += scissorValue + lossValue;
                    break;

                // You should draw
                case 'Y':
                    points += rockValue + drawValue;
                    break;

                // You should win
                case 'Z':
                    points += paperValue + winValue;
                    break;
            }

            break;

        case 'B':
            switch (line[2])
            {
                // You should lose
                case 'X':
                    points += rockValue + lossValue;
                    break;

                // You should draw
                case 'Y':
                    points += paperValue + drawValue;
                    break;

                // You should win
                case 'Z':
                    points += scissorValue + winValue;
                    break;
            }

            break;

        case 'C':
            switch (line[2])
            {
                // You should lose
                case 'X':
                    points += paperValue + lossValue;
                    break;

                // You should draw
                case 'Y':
                    points += scissorValue + drawValue;
                    break;

                // You should win
                case 'Z':
                    points += rockValue + winValue;
                    break;
            }

            break;
    }

Console.WriteLine(points);
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Edit: Lite kodpill

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Dag: 2
SprÄk: Nim
Lösning: Github

Ganska trevlig uppgift idag, men jag misslyckades med att predicta vad part 2 skulle vara sÄ jag generaliserade part 1 pÄ fel saker och koden blev ganska lÄng xD.

include prelude
import std / strscans

type
  Hand = enum
    Rock, Paper, Scissor

let loseTable = {Rock: Paper, Scissor: Rock, Paper: Scissor}.toTable
let winTable = {Rock: Scissor, Scissor: Paper, Paper: Rock}.toTable

proc readInputPart1(input: string, leftMap, rightMap: Table[char, Hand]): tuple[left: seq[Hand], right: seq[Hand]] =
  for line in input.splitLines:
    let (success, l, r) = scanTuple(line, "$c $c")
    assert success
    result.left.add leftMap[l]
    result.right.add rightMap[r]


proc gameScore(opponent, me: Hand): int =
  let shapeScore = {Rock: 1, Paper: 2, Scissor: 3}.toTable
  result = shapeScore[me]
  if me == opponent:
    result += 3
  elif winTable[me] == opponent:
    result += 6

proc part1(input: string) =
  let leftTab = {'A': Rock, 'B': Paper, 'C': Scissor}.toTable
  let rightTab = {'X': Rock, 'Y': Paper, 'Z': Scissor}.toTable
  let (opponent, me) = readInputPart1(input, leftTab, rightTab)
  var score = 0
  for i in 0 .. me.high:
    score += gameScore(opponent[i], me[i])

  echo "Part 1: ", score


proc readInputPart2(input: string, leftMap: Table[char, Hand]): tuple[left: seq[Hand], right: seq[Hand]] =
  for line in input.splitLines:
    let (success, l, r) = scanTuple(line, "$c $c")
    assert success
    let opponent = leftMap[l]
    result.left.add opponent
    if r == 'X':
      result.right.add winTable[opponent]
    elif r == 'Y':
      result.right.add opponent
    elif r == 'Z':
      result.right.add loseTable[opponent]
    else:
      assert false
    
proc part2(input: string) =
  let leftTab = {'A': Rock, 'B': Paper, 'C': Scissor}.toTable
  let (opponent, me) = readInputPart2(input, leftTab)
  var score = 0
  for i in 0 .. me.high:
    score += gameScore(opponent[i], me[i])

  echo "Part 2: ", score

when isMainModule:
  let input = readFile("input.txt")
  part1(input)
  part2(input)
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Dag: 2
SprÄk: Java
Lösning:

import java.io.IOException;
import java.net.URI;
import java.net.http.HttpClient;
import java.net.http.HttpRequest;
import java.net.http.HttpResponse;
import java.util.Map;

public class Application {

    public static void main(String[] args) throws IOException, InterruptedException {
        HttpClient client = HttpClient.newHttpClient();
        HttpRequest request = HttpRequest.newBuilder()
                .GET()
                .uri(URI.create("https://adventofcode.com/2022/day/2/input"))
                .header("Cookie", "session=changeme")
                .build();

        HttpResponse<String> response = client.send(request, HttpResponse.BodyHandlers.ofString());

        String body = response.body();

        var lut = Map.of(
                "A X", 1 + 3,
                "A Y", 2 + 6,
                "A Z", 3 + 0,
                "B X", 1 + 0,
                "B Y", 2 + 3,
                "B Z", 3 + 6,
                "C X", 1 + 6,
                "C Y", 2 + 0,
                "C Z", 3 + 3
        );

        var lut2 = Map.of(
                "A X", 3 + 0,
                "A Y", 1 + 3,
                "A Z", 2 + 6,
                "B X", 1 + 0,
                "B Y", 2 + 3,
                "B Z", 3 + 6,
                "C X", 2 + 0,
                "C Y", 3 + 3,
                "C Z", 1 + 6
        );

        int score = 0;
        for (String line : body.split("\n")) {
            score += lut2.get(line);
        }

    }
}
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Dag: 2
SprÄk: Java
Lösning:

import java.io.*;
import java.util.*;

public class DayTwo {

	public static void main(String[] args) {

		List<Character> opponent = new ArrayList<>();
		List<Character> response = new ArrayList<>();

		try {  
			File file = new File("C:\\AoC 22\\inputDay2.txt");
			FileReader filereader = new FileReader(file);
			BufferedReader bufferedreader = new BufferedReader(filereader);
			String line;  
			while((line = bufferedreader.readLine()) != null) {  
				opponent.add(line.charAt(0));
				response.add(line.charAt(2));
			}
			filereader.close();
		} catch(IOException e) { 
			e.printStackTrace();
		}

		/*
		 * A is for Rock X
		 * B for Paper Y
		 * C for Scissor Z
		 * 
		 *  1 point for Rock
		 *  2 point for Paper
		 *  3 point for Scissor
		 *  
		 *  + outcome of round
		 *  0 point if you lost
		 *  3 point if it was a draw
		 *  6 point if you won 
		 */
		
		int points = 0;
		for(int i = 0; i < opponent.size(); i++) {
			if(response.get(i) == 'X') {
				points = points + 1;
				if(opponent.get(i) == 'A')
					points = points + 3;
				else if(opponent.get(i) == 'C')
					points = points + 6;
			}
			if(response.get(i) == 'Y') {
				points = points + 2;
				if(opponent.get(i) == 'A')
					points = points + 6;
				else if(opponent.get(i) == 'B')
					points = points + 3;
			}
			if(response.get(i) == 'Z') {
				points = points + 3;
				if(opponent.get(i) == 'B')
					points = points + 6;
				else if(opponent.get(i) == 'C')
					points = points + 3;
			}
		}
		System.out.println("part 1 points: " + points);
		
		/*
		 * X is for lose
		 * Y is for draw
		 * Z is for win
		 * 
		 * A is for Rock 	
		 * B for Paper 
		 * C for Scissor 
		 * 
		 * 1 point for Rock
		 * 2 point for Paper
		 * 3 point for Scissor
		 *  
		 * + outcome of round
		 * 0 point if you lost
		 * 3 point if it was a draw
		 * 6 point if you won 
		 */

		int pointsNew = 0;
		for(int i = 0; i < opponent.size(); i++) {
			if(response.get(i) == 'X') {
				if(opponent.get(i) == 'A')
					pointsNew = pointsNew + 3;
				else if(opponent.get(i) == 'B')
					pointsNew = pointsNew + 1;
				else 
					pointsNew = pointsNew + 2;
			}
			if(response.get(i) == 'Y') {
				if(opponent.get(i) == 'A')
					pointsNew = pointsNew + 1 + 3;
				else if(opponent.get(i) == 'B')
					pointsNew = pointsNew + 2 + 3;
				else 
					pointsNew = pointsNew + 3 + 3;
			}
			if(response.get(i) == 'Z') {
				if(opponent.get(i) == 'A')
					pointsNew = pointsNew + 2 + 6;
				else if(opponent.get(i) == 'B')
					pointsNew = pointsNew + 3 + 6;
				else 
					pointsNew = pointsNew + 1 + 6; 
			}
		}
		System.out.println("part 2 points: " + pointsNew);
	}
}
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Dag: 2
SprÄk: JS (Node)

import { input } from '../input/day2.js';

const readInput = (input) => input.split('\n');
const rows = readInput(input);

export const solutionA = () => {
  let hash = {
    'A X': 1 + 3, //rock rock 
    'A Y': 2 + 6, //rock paper
    'A Z': 3 + 0, //rock scissor
    'B X': 1 + 0, //paper rock
    'B Y': 2 + 3, //paper paper
    'B Z': 3 + 6, //paper scissor
    'C X': 1 + 6, //scissor rock
    'C Y': 2 + 0, //scissor paper
    'C Z': 3 + 3, //scissor scissor
  }
  let points = 0;
  for (const row of rows) {
    points += hash[row];
  }
  console.log(points);
}

export const solutionB = () => {
  let hash = {
    'A X': 3 + 0, //rock scissor
    'A Y': 1 + 3, //rock rock
    'A Z': 2 + 6, //rock paper
    'B X': 1 + 0, //paper rock
    'B Y': 2 + 3, //paper paper
    'B Z': 3 + 6, //paper scissor
    'C X': 2 + 0, //scissor paper
    'C Y': 3 + 3, //scissor scissor
    'C Z': 1 + 6, //scissor rock
  }
  let points = 0;
  for (const row of rows) {
    points += hash[row];
  }
  console.log(points);
}
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Dag 2
SprÄk: C#
Kommentarer:

Är skoj att göra pattern matching, Ă€ven om jag nog egentligen hellre gör det efter frukost I efterhand gjorde jag den yttre matchingen pĂ„ första delen av input samt skrev additionerna istĂ€llet för summan direkt för lite bĂ€ttre lĂ€slighet.

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Lösning:

namespace Day2;

internal class Program
{
    static void Main(string[] args)
    {
        using var sr = new StreamReader("input.txt");

        int pt1score = 0;
        int pt2score = 0;
        while (!sr.EndOfStream)
        {
            var line = sr.ReadLine()!.Split(' ');
            pt1score += pt1_calc(line);
            pt2score += pt2_calc(line);
        }
        Console.WriteLine($"Part 1 = {pt1score}");
        Console.WriteLine($"Part 2 = {pt2score}");

        int pt1_calc(string[] strings)
        {
            return strings[0] switch
            {
                "A" => strings[1] switch { "X" => 1 + 3, "Y" => 2 + 6, "Z" => 3 + 0, _ => 0 },
                "B" => strings[1] switch { "X" => 1 + 0, "Y" => 2 + 3, "Z" => 3 + 6, _ => 0 },
                "C" => strings[1] switch { "X" => 1 + 6, "Y" => 2 + 0, "Z" => 3 + 3, _ => 0 },
                _ => 0
            };
        }

        int pt2_calc(string[] strings)
        {
            return strings[0] switch
            {
                "A" => strings[1] switch { "X" => 3 + 0, "Y" => 1 + 3, "Z" => 2 + 6, _ => 0 },
                "B" => strings[1] switch { "X" => 1 + 0, "Y" => 2 + 3, "Z" => 3 + 6, _ => 0 },
                "C" => strings[1] switch { "X" => 2 + 0, "Y" => 3 + 3, "Z" => 1 + 6, _ => 0 },
                _ => 0
            };
        }

    }
}
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Skrivet av GLaDER:

Dag: 1
SprÄk: Python 3
Lösning: GitHub

Dumma Wastl roterade tydligen cookies nÄgon gÄng under veckan, för nÀr jag skulle köra mitt fetch-script blev jag promptad att logga in. Jag spenderade flera dyrbara minuter innan jag tillslut gjorde som "folk" och bara kopierade input frÄn hemsidan...

Bra första uppgift, tycker jag. Det som tog tid (förutom fadÀsen ovan) var att splitta input pÄ rÀtt sÀtt.

def solution_1(input):
    max_cal = 0
    for e in input:
        max_cal = max((sum(map(int, e.split()))), max_cal)
    return max_cal

def solution_2(input):
    elfs = list()
    for e in input:
        elfs.append(sum(map(int, e.split())))
    return sum(sorted(elfs, reverse=True)[:3])
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GÄ till inlÀgget

Dag: 2
SprÄk: Python 3
Lösning: GitHub

Ganska rak och enkel uppgift, men det gÀllde att hÄlla tungan i rÀtt mun.

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Dag: 2
SprÄk: Knackig F#

open System.IO

type Shape =
    | Rock
    | Paper
    | Scissor
    
type Outcome =
     | Win
     | Lose
     | Draw

let scoreHand hand1 hand2 =
    match (hand1,hand2) with
    | Rock, Paper -> Win
    | Rock, Scissor -> Lose
    | Paper, Rock -> Lose
    | Paper, Scissor -> Win
    | Scissor, Rock -> Win
    | Scissor, Paper -> Lose
    | _ -> Draw
    
let getHand hand outcome =
    match (hand, outcome) with
    | x, Draw -> x
    | Rock, Win -> Paper
    | Rock, Lose -> Scissor
    | Paper, Win -> Scissor
    | Paper, Lose -> Rock
    | Scissor, Win -> Rock
    | Scissor, Lose -> Paper

let scoreOutcome result =
    match result with
    | Win -> 6
    | Draw -> 3
    | Lose -> 0
let scoreShape shape = match shape with
                             | Rock -> 1
                             | Paper -> 2
                             | Scissor -> 3

let parseShape r =
    match r with
    | "A" -> Rock
    | "B" -> Paper
    | "C" -> Scissor
    | "X" -> Rock
    | "Y" -> Paper
    | "Z" -> Scissor
         
let parseOutcome r =
    match r with
    | "X" -> Lose
    | "Y" -> Draw
    | "Z" -> Win
let task' parser1 parser2 = File.ReadAllLines "input.txt" |> Seq.map (fun s ->
    let parts = s.Split(" ")
    (parser1 parts[0], parser2 parts[1]))

    
let task1 = task' parseShape parseShape |> Seq.map(fun (h1,h2) -> scoreShape h2 + (scoreHand h1 h2 |> scoreOutcome)) |> Seq.sum
let task2 = task' parseShape parseOutcome  |> Seq.map(fun (h,o) -> ((getHand h o |> scoreShape) + scoreOutcome o)) |> Seq.sum

printfn $"Task 1: %i{task1}"
printfn $"Task 2: %i{task2}"
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Dag 2
SprÄk: Java

package aoc_template;
import java.io.*;
import java.util.*;

public class Aoc_template {
    public static void main(String[] args) {
        
        List<String> my_play = new ArrayList<>();
        List<String> opp_play = new ArrayList<>();
        
        // Rock
        int score_rock = 1;
        
        // Paper
        int score_paper = 2;
        
        // Scissors
        int score_scissor = 3;
        
        // Score for win
        int score_win = 6;
        
        // Score for draw
        int score_draw = 3;
        
        // Score for lose
        int score_lose = 0;
        
        // Total score
        int total_score = 0;
        int total_score_two = 0;
        
        
        try  
        {  
            File file=new File("C:/aoc_input/02/input.txt");
            FileReader fr=new FileReader(file);
            BufferedReader br=new BufferedReader(fr);
            StringBuffer sb=new StringBuffer();
            String line;  
            
            while((line=br.readLine())!=null)  
            {  
                String opponent_side = line.substring(0,1);
                String my_side = line.substring(2,3);
                my_play.add(my_side);
                opp_play.add(opponent_side);
            }
            fr.close();
        }  
        catch(IOException e)  
        {  
            e.printStackTrace();
        }
/////////////////////////////////////////// START PART 1 /////////////////////////////////////////////////////

/*
   My side

   X = ROCK
   Y = PAPER
   Z = SCISSORS

    Opponent side

   A = ROCK
   B = PAPER
   C = SCISSORS
*/
        for (int i = 0; i<my_play.size();i++) {
            switch(opp_play.get(i)) {
           
            case "A": // Rock
                if (my_play.get(i).equals("X")) {
                    // DRAW WITH ROCK 
                    total_score = total_score + score_rock + score_draw;
                }
                if (my_play.get(i).equals("Y")) {
                    // WIN WITH PAPER
                    total_score = total_score + score_paper + score_win;
                }
                    // LOSE WITH SCISSORS
                if (my_play.get(i).equals("Z")) {
                    total_score = total_score + score_scissor + score_lose;
                }
                break;
            
            case "B": // Paper
                if (my_play.get(i).equals("Y")){
                    // DRAW WITH PAPER
                    total_score = total_score + score_paper + score_draw;
                }
               if (my_play.get(i).equals("Z")) {
                    // WIN WITH SCISSORS
                    total_score = total_score + score_scissor + score_win;
                }
                    // LOSE WITH ROCK
                if (my_play.get(i).equals("X")) {
                    total_score = total_score + score_rock + score_lose;
                }
                break;
           
            case "C": // Scissors
                // Eqaul with scissors
                if (my_play.get(i).equals("Z")) {
                    total_score = total_score + score_scissor + score_draw;
                }
                // Win with rock
                if (my_play.get(i).equals("X")) {
                    total_score = total_score + score_rock + score_win;
                }
                // Lose with paper
                if (my_play.get(i).equals("Y")) {
                    total_score = total_score + score_paper + score_lose;
                }
                break;
            }
        }
        
       
/////////////////////////////////////////// END PART 1 //////////////////////////////////////////////////////

/////////////////////////////////////////// START PART 2 ////////////////////////////////////////////////////

/*
    If i get Y = draw
    If i get X = lose
    If i get Z = win

    My side
    X = ROCK
    Y = PAPER
    Z = SCISSORS

    Opponent side

    A = ROCK
    B = PAPER
    C = SCISSORS

*/
    
    
    for (int i = 0; i<my_play.size();i++){
        switch (my_play.get(i)) {
            case "Y": // Y = DRAW
                if (opp_play.get(i).equals("A")){
                    total_score_two = total_score_two + score_rock + score_draw;
                }
                if (opp_play.get(i).equals("B")) {
                    total_score_two = total_score_two + score_paper + score_draw;
                }
                if (opp_play.get(i).equals("C")){
                    total_score_two = total_score_two + score_scissor + score_draw;
                }
                break;
                
            
            case "X": // X = LOSE
                if (opp_play.get(i).equals("A")) {
                    total_score_two = total_score_two + score_lose + score_scissor;
                }
                if (opp_play.get(i).equals("B")){
                    total_score_two = total_score_two + score_lose + score_rock;
                }
                
                if (opp_play.get(i).equals("C")) {
                    total_score_two = total_score_two + score_lose + score_paper;
                }
                break;
                
            
            case "Z": // Z = WIN
                if ((opp_play.get(i).equals("A"))) {
                    total_score_two = total_score_two + score_paper + score_win;
                }
                if (opp_play.get(i).equals("B")) {
                    total_score_two = total_score_two + score_scissor + score_win;
                }
                if (opp_play.get(i).equals("C")) {
                    total_score_two = total_score_two  + score_rock + score_win;
                }
                break;
        }
    }
    /////////////////////////////////////////// END PART 2 /////////////////////////////////////////////////////
    
    // Print the scores
    System.out.println("Score part 1: " + total_score);
    System.out.println("Score part 2: " + total_score_two);
    }  

}
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Dag: 2
SprÄk: Kotlin

fun part2Day2(lines: List<String>): Int {
	var score = 0
	for (line in lines) {

		score += when (line[2]) {
			'Z' -> 6
			'Y' -> 3
			else -> 0
		}

		val shift = when (line[2]) {
			'X' -> -1
			'Y' -> 0
			else  -> 1
		}

		score += when (line[0]) {
			'A' -> (300 + shift) % 3 + 1
			'B' -> (301 + shift) % 3 + 1
			else -> (302 + shift) % 3 + 1
		}
	}
	return score
}

fun part1Day2(lines: List<String>): Int {
	var score = 0
	for (line in lines) {
		score += when (line[0] - line[2] + 23) {
			0 -> 3
			-1, 2 -> 6
			else -> 0
		}

		score += when (line[2]) {
			'X' -> 1
			'Y' -> 2
			'Z' -> 3
			else -> 0
		}
	}
	return score
}
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Älskar verkligen Kotlins "when". SĂ„ mycket finare Ă€n Javas switchar.

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Skrivet av johanandersson:

Dag: 2
SprÄk: Kotlin

fun part2Day2(lines: List<String>): Int {
	var score = 0
	for (line in lines) {

		score += when (line[2]) {
			'Z' -> 6
			'Y' -> 3
			else -> 0
		}

		val shift = when (line[2]) {
			'X' -> -1
			'Y' -> 0
			else  -> 1
		}

		score += when (line[0]) {
			'A' -> (300 + shift) % 3 + 1
			'B' -> (301 + shift) % 3 + 1
			else -> (302 + shift) % 3 + 1
		}
	}
	return score
}

fun part1Day2(lines: List<String>): Int {
	var score = 0
	for (line in lines) {
		score += when (line[0] - line[2] + 23) {
			0 -> 3
			-1, 2 -> 6
			else -> 0
		}

		score += when (line[2]) {
			'X' -> 1
			'Y' -> 2
			'Z' -> 3
			else -> 0
		}
	}
	return score
}
Dold text

Älskar verkligen Kotlins "when". SĂ„ mycket finare Ă€n Javas switchar.

GÄ till inlÀgget

Python har nÄgot liknande sen 3.10, det heter match statements.

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Dag:2
SprÄk: Python (som jag aldrig anvÀnd innan)

Som vanligt följer jag KISS principen:

def day2():
    input_list = open("data\\day2.txt").read().split("\n")
    part1_score = 0
    part2_score = 0
    win = 6
    draw = 3
    loss = 0
    rock = 1
    paper = 2
    scissors = 3

    for game_round in input_list:
        match game_round:
            case "A X":
                part1_score += draw + rock
                part2_score += loss + scissors
            case "A Y":
                part1_score += win + paper
                part2_score += draw + rock
            case "A Z":
                part1_score += loss + scissors
                part2_score += win + paper
            case "B X":
                part1_score += loss + rock
                part2_score += loss + rock
            case "B Y":
                part1_score += draw + paper
                part2_score += draw + paper
            case "B Z":
                part1_score += win + scissors
                part2_score += win + scissors
            case "C X":
                part1_score += win + rock
                part2_score += loss + paper
            case "C Y":
                part1_score += loss + paper
                part2_score += draw + scissors
            case "C Z":
                part1_score += draw + scissors
                part2_score += win + rock

    print(part1_score)
    print(part2_score)

    #Execution time (ms): 0.5049000028520823
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Skrivet av pine-orange:

Python har nÄgot liknande sen 3.10, det heter match statements.

GÄ till inlÀgget

Jag har testat det lite, men ska det gÄ att anvÀnda för assignment pÄ samma fina sÀtt?

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Dag: 2
SprÄk: Python (oneliner)

print([sum([(lambda x,y,f: "XYZXY"["BCA".find(x):].find(f(x, y)) * 3
                           + " XYZ".find(f(x, y)))(*e, f)
            for e in [p.split() for p in open("input02").read().split('\n')]])
       for f in [ lambda x, y: y,
                  lambda x, y: "XYZXY"["BCA".find(x) + "XYZ".find(y)]]])
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Dag: 2
SprÄk: C#
Lösning: Github

FortsÀtter med hemsk kod bara för att lösa problemet. I Är Àr mest att klara sÄ mÄnga som möjligt. (Som varje Är)

Kodar inte dagligen lÀngre. Och innan var det mest PHP.

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Dag: 2
SprÄk: Rust

GÄr att göra mycket smartare saker, men eftersom man inte visste vad del tvÄ skulle handla om sÄ var det svÄrt att optimera innan.

Visst, det Àr enklare att koda detta i Python eller JS, men för att vara ett sÄ pass lÄgnivÄsprÄk Àr Rust vÀldigt trevligt 

fn calculate_score1(opponent: char, you: char) -> usize {
   return if you == 'X' { 1 + if opponent == 'A' { 3 } else if opponent == 'C' { 6 } else { 0 }}
     else if you == 'Y' { 2 + if opponent == 'A' { 6 } else if opponent == 'B' { 3 } else { 0 }}
     else if you == 'Z' { 3 + if opponent == 'B' { 6 } else if opponent == 'C' { 3 } else { 0 }}
     else { 0 };
}

fn calculate_score2(opponent: char, result: char) -> usize {
    return if result == 'Z' { 6 + if opponent == 'A' { 2 } else if opponent == 'B' { 3 } else if opponent == 'C' { 1 } else { 0 }}
      else if result == 'Y' { 3 + if opponent == 'A' { 1 } else if opponent == 'B' { 2 } else if opponent == 'C' { 3 } else { 0 }}
      else if result == 'X' { 0 + if opponent == 'A' { 3 } else if opponent == 'B' { 1 } else if opponent == 'C' { 2 } else { 0 }}
      else { 0 };
}

fn main() {
    let input = include_str!("./input.txt");
    let mut total_score1 = 0;
    let mut total_score2 = 0;

    for line in input.lines() {
        total_score1 +=
            calculate_score1(line.chars().nth(0).unwrap(), line.chars().nth(2).unwrap());
        total_score2 +=
            calculate_score2(line.chars().nth(0).unwrap(), line.chars().nth(2).unwrap());
    }

    println!("Total Score 1 {}", total_score1);
    println!("Total Score 2 {}", total_score2);
}
}
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Dag: 2
SprÄk: Haskell

Modulo, modulo. Hemskt mycket modulo!

-- The program expects the input on stdin, ie
-- $ ./solve < input

import Data.List (elemIndex)

main = interact solve

solve :: String -> String
solve input = "Problem 1: " ++ show score1 ++ "\n"
           ++ "Problem 2: " ++ show score2 ++ "\n"
    where score1 = foldr score 0 (map shapes (lines input))
          score2 = foldr score 0 (map shapes2 (lines input))

score :: (Int, Int) -> Int -> Int
score (oppShape, myShape) acc = acc + myShape + gameScore oppShape myShape
    where gameScore opp me = 3*mod (1+mod (3+me-opp) 3) 3

shapes :: String -> (Int, Int)
shapes s = (shape $ head s, shape $ last s)

shapes2 :: String -> (Int, Int)
shapes2 s = (shape $ head s, 1 + mod (shape (head s) + shape (last s)) 3)

shape :: Char -> Int
shape c = case elemIndex c "ABCXYZ" of
    Just i -> 1 + mod i 3
    _ -> 0

(AnvÀnder highlight som finns i apt för syntaxfÀrgning).

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Skrivet av Ingetledigtnamn:

Dag: 2
SprÄk: Python (oneliner)

print([sum([(lambda x,y,f: "XYZXY"["BCA".find(x):].find(f(x, y)) * 3
                           + " XYZ".find(f(x, y)))(*e, f)
            for e in [p.split() for p in open("input02").read().split('\n')]])
       for f in [ lambda x, y: y,
                  lambda x, y: "XYZXY"["BCA".find(x) + "XYZ".find(y)]]])
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GÄ till inlÀgget

NÀr man ser en one-liner nÀr man gjort det i Java pÄ 194 rader isch (iofs kommentarer inkluderat) sÄ förstÄr man hur mycket lÀttare allt gÄr att göra :')

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Dag: 2
SprÄk: C#

private (int partOne, int partTwo) Solve(string input)
	{
        (int playerOnePoints, int playerTwoPoints) GetPoints(char p1, char p2, bool forceOutcome = false)
        {
            int p1a = (int)p1 - 64; // 1,2,3
            int p2a = (int)p2 - 87; // 1,2,3

            if (forceOutcome) // part two
            {
                p2a = p2a switch
                {
                    1 => p1a switch { 1 => 3, 2 => 1, 3 => 2, _ => 0 }, /*loss*/
                    2 => p1a, /* draw */
                    3 => p1a switch { 1 => 2, 2 => 3, 3 => 1, _ => 0 }, /*win*/
                    _ => 0
                };
            }

            switch (p1a - p2a)
            {
                case 1:
                case -2:/*win p1*/
                    return (p1a + 6, p2a + 0);
                case -1:
                case 2: /*win p2*/
                    return (p1a + 0, p2a + 6);
                default:
                case 0: /*draw*/
                    return (p1a + 3, p2a + 3);
            }

        }

        var collectionOfPoints = input
            .ToLines()
            .Select( line =>
                 /* tuple with partOne, partTwo points */
                 (GetPoints(line[0], line[2]).playerTwoPoints, GetPoints(line[0], line[2], forceOutcome: true).playerTwoPoints)
        ).ToList();

        var result_1 = collectionOfPoints.Select(players => players.Item1).Sum();
        var result_2 = collectionOfPoints.Select(players => players.Item2).Sum();

        return (result_1, result_2);
	}

** .ToLines() Àr min egna funktion som splittar pÄ \n

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Är mest en plojgrej men bestĂ€mde mig för att visualisera alla matcherna man fick i inputen med hjĂ€lp av emojis och en wrapper för P5.js i Nim. Om nĂ„gon Ă€r intresserad kan dom se den hĂ€r. Den animerar varje match separat pĂ„ ett stort grid och visar emojis som representerar dom olika valen (sten, sax, pĂ„se) samt utfallet i matchen (grön bock för vinst, streck för oavgjort, rött kryss för förlust).

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Dag 2 Java.

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.util.ArrayList;

public class Day2 {
    public static void main(String[] args) throws IOException {

        //a rock, b paper, c scissor
        int xRock = 1;
        int yPaper = 2;
        int zScissors = 3;
        int win = 6;
        int tie = 3;
        int pointCounter1 = 0;
        int pointCounter2 = 0;

        Path filePath = Path.of("src/input02.txt");
        String day2Content = Files.readString(filePath);

        ArrayList<String> guideList = new ArrayList<>();

        StringBuilder builder = new StringBuilder();
        for (int i = 0; i < day2Content.length(); i++) {
            if (day2Content.charAt(i) != ('\n')) {
                builder.append(day2Content.charAt(i));
            }
            else {
                guideList.add(builder.toString());
                builder = new StringBuilder();
            }
        }

        for (String one : guideList) {
            switch (one) {
                case "A X" -> pointCounter1 += (xRock + tie);
                case "A Y" -> pointCounter1 += (yPaper + win);
                case "A Z" -> pointCounter1 += zScissors;
                case "B X" -> pointCounter1 += xRock;
                case "B Y" -> pointCounter1 += (yPaper + tie);
                case "B Z" -> pointCounter1 += (zScissors + win);
                case "C X" -> pointCounter1 += (xRock + win);
                case "C Y" -> pointCounter1 += yPaper;
                case "C Z" -> pointCounter1 += (zScissors + tie);
            }
        }

        for (String two : guideList) {
            switch (two) {
                case "A X" -> pointCounter2 += zScissors;
                case "A Y" -> pointCounter2 += (tie + xRock);
                case "A Z" -> pointCounter2 += (win + yPaper);
                case "B X" -> pointCounter2 += xRock;
                case "B Y" -> pointCounter2 += (tie + yPaper);
                case "B Z" -> pointCounter2 += (win + zScissors);
                case "C X" -> pointCounter2 += yPaper;
                case "C Y" -> pointCounter2 += (tie + zScissors);
                case "C Z" -> pointCounter2 += (win + xRock);
            }
        }
        System.out.println(pointCounter1);
        System.out.println(pointCounter2);
    }
}
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